document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841963>Question 841963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle has a length of 20 cm. the sum of the lengths of the other two sides is 28 cm. find the length of the longer of the two sides of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507295 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16 and 12 are possible sides<BR>\n" );
document.write( "256+144=400<BR>\n" );
document.write( "16^2+12^2=20^2<BR>\n" );
document.write( "multiple of the 3,4,5 triangle<BR>\n" );
document.write( "x+y=28,<BR>\n" );
document.write( "x^2+y^2=20^2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );