document.write( "Question 841926: |2x-1|=5 i really have no idea how to start this
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #507268 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! The entire left side as an absolute value could be treated as a variable. It MUST be positive, being an absolute value, and it is. The right hand member is positive 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You know |2x-1| is positive, but you must allow for 2x-1 being separately positive(or zero) and negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the case \n" ); document.write( "|2x-1|=2x-1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the case \n" ); document.write( "|2x-1|=-(2x-1)=1-2x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do you know what to do now? \n" ); document.write( " |