document.write( "Question 841914: Really confused and need help with this problem:\r
\n" ); document.write( "\n" ); document.write( "Log(base3)x=Log(base9)6x
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Algebra.Com's Answer #507256 by josgarithmetic(39626)\"\" \"About 
You can put this solution on YOUR website!
\"log%283%2Cx%29=log%289%2C6x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Change of Base Formula: \"highlight_green%28log%28b%2Cx%29=log%28a%2Cx%29%2Flog%28a%2Cb%29%29\"\r
\n" ); document.write( "\n" ); document.write( "The right hand side of the given equation should be converted to base 3.
\n" ); document.write( "\"log%289%2C6x%29=log%283%2C6x%29%2Flog%283%2C9%29\"
\n" ); document.write( "\"log%289%2C6x%29=%281%2F2%29log%283%2C6x%29\"
\n" ); document.write( "Using that in the original given equation,\r
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\n" ); document.write( "\n" ); document.write( "\"log%283%2Cx%29=%281%2F2%29log%283%2C6x%29\"
\n" ); document.write( "\"2log%283%2Cx%29=log%283%2C6x%29\"
\n" ); document.write( "\"log%283%2Cx%5E2%29=log%283%2C6x%29\"\r
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\n" ); document.write( "\n" ); document.write( "The antilog of left and right can be taken, and the arguments inside the log function are equated, and ....
\n" ); document.write( "\"x%5E2=6x\"
\n" ); document.write( "\"x%5E2-6x=0\"
\n" ); document.write( "\"x%28x-6%29=0\"
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\n" ); document.write( "\"highlight%28x=0%29\" or \"highlight%28x=6%29\"
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