document.write( "Question 841860: 1-2cos^2x=(tan^2x-1)/(tan^2x+1)
\n" ); document.write( "i need help with this equation. i need to have it in a t-table format. can you please help me?!
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Algebra.Com's Answer #507246 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1-2cos^2x=(tan^2x-1)/(tan^2x+1)
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\n" ); document.write( "(1-cos^2(x)-cos^2(x) = (tan^2(x)-1)/sec^2(x)
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\n" ); document.write( "sin^2(x)-cos^2(x) = (tan^2(x)-1)/sec^2(x)
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\n" ); document.write( "Cross-multiply to get:
\n" ); document.write( "sin^2(x)*sec^2(x) - 1 = tan^2(x)-1
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\n" ); document.write( "sin^2(x)/cos^2(x) - 1 = tan^2(x)-1
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\n" ); document.write( "tan^2(x)-1 = tan^2(x)-1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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