document.write( "Question 841871: a 60% sulphuric acid solution will be mixed with a 90% sulphuric acid solution to produce 8 L of a 75% solution. how much of each is required \n" ); document.write( "
Algebra.Com's Answer #507230 by josgarithmetic(39617)\"\" \"About 
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You will need the densities of sulfuric acid solutions. Check this:
\n" ); document.write( "http://www.chembuddy.com/?left=CASC&right=density_tables\r
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\n" ); document.write( "\n" ); document.write( "60%_________1.5031 g/cc
\n" ); document.write( "90%_________1.8197
\n" ); document.write( "Unless you can find another data source (like maybe a handbook), you might try estimating the 75% concentration density, \"%281.615%2B1.7323%29%2F2=1.6736\" g/cc, only an estimate or prediction.\r
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\n" ); document.write( "\n" ); document.write( "You did not say if your concentrations are w/w or w/v. You probably expect to use percent w/v. But the data in the reference source is percents w/w.\r
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\n" ); document.write( "\n" ); document.write( "Let x = volume, ml, or the 60%
\n" ); document.write( "Let y = volume, ml, of the 90%
\n" ); document.write( "And assuming volumes are simply additive:\r
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\n" ); document.write( "\n" ); document.write( "Pure sulfuric acid: \"x%2A1.5031%2A%280.60%29%2By%2A1.8197%2A%280.90%29\" grams of sulfuric acid.
\n" ); document.write( "Volume of 75% solution: \"%281.6736%29%28x%2By%29\" grams of solution.\r
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\n" ); document.write( "\n" ); document.write( "Compose the percentage equation to be all as percent by weight.
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\n" ); document.write( "\n" ); document.write( "The volume sum equation is just \"highlight%28x%2By=8000%29\", using milliliters.\r
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\n" ); document.write( "\n" ); document.write( "Those two red-highlited equations are the system to solve, for x and y.
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