document.write( "Question 841804: (20 - r)^1/2 = r
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Algebra.Com's Answer #507210 by richwmiller(17219)\"\" \"About 
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(20 - r)^1/2 = r
\n" ); document.write( "(20 - r) = r^2
\n" ); document.write( "0=r^2+r-20
\n" ); document.write( "0=(r+5)*(r-4)
\n" ); document.write( "(20 - (-5))^1/2 = -5
\n" ); document.write( "25^1/2=-5
\n" ); document.write( "extraneous
\n" ); document.write( "(20 - 4)^1/2 =4
\n" ); document.write( "16^1/2=4\r
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