document.write( "Question 9360: A two-digit number is such that the product of its digits is 12.When 36 is added to this number, the digits interchange their places.Find the number. \n" ); document.write( "
Algebra.Com's Answer #5072 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! let the 2-digit number be thought of as xy. This means the number is really 10x+y, as 34 means 30+4--> 3x10 + 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Product is xy = 12 --eqn1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "straightaway, this means we have either 26 or 34. Looking at these, adding 36 to both gives 62 or 70. So the answer is 26.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Anyway, algebraically...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "adding 36 to the number is 10x+y+36 \n" ); document.write( "and this equals \"yx\" or rather 10y+x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, 10x+y+36 = 10y+x \n" ); document.write( "--> 9x - 9y = -36 \n" ); document.write( "--> x - y = -4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and subbing in eqn1 into this gives \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(y+2)(y-6) = 0 \n" ); document.write( "so y = -2 or y=6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ignore the -2 value...we are looking for a positive number, so y=6. Hence from eqn1, x = 2...number is 26!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |