document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841669>Question 841669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 6in longer than its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is 44in , find its area.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507172 by </B><A HREF=/tutors/aboutme.mpl?userid=Narsinghchauhan8960103366><B>Narsinghchauhan8960103366(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Narsinghchauhan8960103366><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Narsinghchauhan8960103366><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width of rectangle is x in<BR>\n" );
document.write( "So the length is (x+6) in<BR>\n" );
document.write( "According to question <BR>\n" );
document.write( "Perimeter of Rectangle =2(length+width)<BR>\n" );
document.write( "44=2[(x+6)+x]<BR>\n" );
document.write( "44=2(2x+6)<BR>\n" );
document.write( "44=4x+12<BR>\n" );
document.write( "4x=44-12=32<BR>\n" );
document.write( "x=32/4=8 in<BR>\n" );
document.write( "width =8 in<BR>\n" );
document.write( "length =8+6=14<BR>\n" );
document.write( "Perimeter of Rectangle = length*width<BR>\n" );
document.write( "=14*8=112 square in </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );