document.write( "Question 70989: Not in book.\r
\n" ); document.write( "\n" ); document.write( "Jim's brakes charges $25 for parts and $55 per hour to fix the brakes on a car. Myron's Auto charges $40 for parts and $30 per hour to do the same job. What length of job in hours would have the smae cost of both shops?\r
\n" ); document.write( "\n" ); document.write( "Thank you for helping me. I hate written problems
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Algebra.Com's Answer #50714 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
For Jim's brakes use the equation: \"y=25%2B55x\" and for Myron use \"y=40%2B30x\"
\n" ); document.write( "To find out when they will cost the same, set the two equations equal to each other (in other words set the two unknown prices equal to each other)
\n" ); document.write( "\"25%2B55x=40%2B30x\"Solve for x (the time)
\n" ); document.write( "\"25x=15\"
\n" ); document.write( "\"x=15%2F25\"
\n" ); document.write( "\"x=3%2F5\"So at 3/5 of an hour or at 36 minutes they will cost the same
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