document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841722>Question 841722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution of the equation? Eliminate any extraneous solutions. sqrt (3x+28)-8=x\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507138 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt (3x+28)-8=x<BR>\n" );
document.write( "(3x+28)=(8+x)^2\r<BR>\n" );
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document.write( "(3x+28)=64+16x+x^2<BR>\n" );
document.write( "x^2+13x+36=0<BR>\n" );
document.write( "(x+4)*(x+9)=0<BR>\n" );
document.write( "x=-4 x=-9<BR>\n" );
document.write( "Try them in the original equation<BR>\n" );
document.write( "sqrt (-12+28)-8=-4<BR>\n" );
document.write( "sqrt(16)-8=-4<BR>\n" );
document.write( "4-8=-4<BR>\n" );
document.write( "sqrt (-27+28)-8=-9<BR>\n" );
document.write( "sqrt(1)-8==9<BR>\n" );
document.write( "-1-8=-9<BR>\n" );
document.write( "x=-9<BR>\n" );
document.write( "-9 is an extraneous root but I am not sure why<BR>\n" );
document.write( "x=-4 </SPAN>\n" );
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