document.write( "Question 70946: 3+|1-(x/2)|>=5 \n" ); document.write( "

Algebra.Com's Answer #50713 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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3 + |1-(x/2)| >= 5
\n" ); document.write( ":
\n" ); document.write( "subtract 3 from both sides:
\n" ); document.write( "|1 - (x/2)| >= 5 - 3
\n" ); document.write( "|1 - (x/2)| >= 2
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\n" ); document.write( "Two situations when you remove the abs
\n" ); document.write( "one
\n" ); document.write( "1 - (x/2) >= 2
\n" ); document.write( ":
\n" ); document.write( "Subtract 1 from both sides:
\n" ); document.write( "-(x/2) >= 2 - 1
\n" ); document.write( "-(x/2) >= 1
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 2 and you have:
\n" ); document.write( "-x >= 2
\n" ); document.write( ":
\n" ); document.write( "We want x to be positive, mult by -1, you must reverse the inequality sign
\n" ); document.write( "x <= -2
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\n" ); document.write( "Situation 2:
\n" ); document.write( "1 - (x/2) <= -2
\n" ); document.write( ":
\n" ); document.write( "Subtract 1 from both sides:
\n" ); document.write( "-(x/2) <= -2 - 1
\n" ); document.write( "-(x/2) <= -3
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 2 and you have:
\n" ); document.write( "-x <= -6
\n" ); document.write( ":
\n" ); document.write( "We want x to be positive, mult by -1, you must reverse the inequality sign
\n" ); document.write( "x >= 6
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Solutions x <= -2; x >= 6 \n" ); document.write( "

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