document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841663>Question 841663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the degree measures of two complementary angles are in the ratio of 2 to 13 , then what is the degree measure of the smaller angle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #507118 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=507118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the degree measures of two complementary angles are in the ratio of 4 to 11, then what is the degree measure of the smaller angle?<BR>\n" );
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document.write( "4 times something + 11 times something = 90<BR>\n" );
document.write( "15*s = 90<BR>\n" );
document.write( "x = 6<BR>\n" );
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document.write( "--> angles of 4*6 & 11*6<BR>\n" );
document.write( "--> 24 & 66 degs<BR>\n" );
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document.write( "Do it like that. </SPAN>\n" );
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