document.write( "Question 841635: Graph each parabola by hand. Give the vertex, axis, domain, and range.\r
\n" ); document.write( "\n" ); document.write( "x = 2/3y^2 - 4y + 8\r
\n" ); document.write( "\n" ); document.write( "My work thus far: \r
\n" ); document.write( "\n" ); document.write( "x = 2/3y^2 - 4y + 8\r
\n" ); document.write( "\n" ); document.write( "x - 8 = 2/3y^2 - 4y\r
\n" ); document.write( "\n" ); document.write( "x - 8 = 2/3(y^2 - 6y)\r
\n" ); document.write( "\n" ); document.write( "x - 8 + 9 = 2/3(y^2 - 6y + 9) * After completing the square\r
\n" ); document.write( "\n" ); document.write( "x + 1 = 2/3(y - 3)^2\r
\n" ); document.write( "\n" ); document.write( "3/2(x + 1) = (y - 3)^2\r
\n" ); document.write( "\n" ); document.write( "Finally ends up in the right form, however, based on this equation my vertex would be: (-1,3), while the book answer is (2,3).. Any help would be appreciated! \n" ); document.write( "

Algebra.Com's Answer #507077 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "x = 2/3y^2 - 4y + 8 
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document.write( " x - 8 = 2/3y^2 - 4y 
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document.write( " x - 8 = 2/3(y^2 - 6y)  Completing Square
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document.write( " x-8 = 
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document.write( "x-8 = 
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document.write( "x-8 + 6 = 
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document.write( " x-2 = 
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document.write( "x =    V(2,3) axis is horizontal line y = 3
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document.write( "domain  x ≥ 2 Parabola opening right.  (Sketch it)
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document.write( "range: All real numbers\r
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document.write( "the vertex form of a Parabola opening right(a>0) or 
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document.write( " where(h,k) is the vertex and  y = k  is the Line of Symmetry\r
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