document.write( "Question 841615: 3x^2 + 2 1/2 x = -2\r
\n" ); document.write( "\n" ); document.write( "A x = {-5 +- i[SQRT(71)}/12
\n" ); document.write( "Bx = {5 +- i[SQRT(71)]}/12
\n" ); document.write( "Cx = {-2 +- i[SQRT(12)]}/7
\n" ); document.write( "Dx = {2 +- i[SQRT(17)]}/-7
\n" ); document.write( "E x = {-3 +- i[SQRT(17)]}/12
\n" ); document.write( "F x = {3 +- i[SQRT(71)]}/-12 \n" ); document.write( "

Algebra.Com's Answer #507071 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "3x^2 + 2 1/2 x = -2 
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document.write( "3x^2 + 2 1/2 x + 2 = 0
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document.write( "  6x^2 + 5x + 4 = 0    |format:  a^2 + bx + c
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