document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70971>Question 70971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this three problems i've tried them every way possible but i don't get the answer. I have the answers but i don't know how to get to them.<BR>\n" );
document.write( "so i can understand them and do my own homework. please help.\r<BR>\n" );
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document.write( "Problem# 30 for chapter 9.5<BR>\n" );
document.write( "Solve each of the equaitons . Be sute to show how to check the solutions.\r<BR>\n" );
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document.write( "inside of the square root it has : 2y+7 then space +4 = y\r<BR>\n" );
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document.write( "Problem # 16 from chapter 9.6\r<BR>\n" );
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document.write( "Geometry. For the home described in exercise 15, if the roof is 7m from peak to eave and the attic space is 3m high at the peak, how long does each of the pieces of insultaion need to be? round to the nearest tenth.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50707 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> #30. Solve:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282y%2B7%29%2B4+=+y ALIGN=MIDDLE  ALT=\"sqrt%282y%2B7%29%2B4+=+y\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 4 from both sides of the equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282y%2B7%29+=+y-4 ALIGN=MIDDLE  ALT=\"sqrt%282y%2B7%29+=+y-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now square both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y%2B7+=+%28y-4%29%5E2 ALIGN=MIDDLE  ALT=\"2y%2B7+=+%28y-4%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify the right side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y%2B7+=+y%5E2-8y%2B16 ALIGN=MIDDLE  ALT=\"2y%2B7+=+y%5E2-8y%2B16\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract (2y+7) from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2-10y%2B9+=+0 ALIGN=MIDDLE  ALT=\"y%5E2-10y%2B9+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor the quadratic equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28y-1%29%28y-9%29+=+0 ALIGN=MIDDLE  ALT=\"%28y-1%29%28y-9%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Apply the zero product principle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-1+=+0 ALIGN=MIDDLE  ALT=\"y-1+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > and/or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-9+=+0 ALIGN=MIDDLE  ALT=\"y-9+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+1 ALIGN=MIDDLE  ALT=\"y+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+9 ALIGN=MIDDLE  ALT=\"y+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "y = 1<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%281%29%2B7%29+%2B+4+=+1 ALIGN=MIDDLE  ALT=\"sqrt%282%281%29%2B7%29+%2B+4+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%289%29%2B4+=+1 ALIGN=MIDDLE  ALT=\"sqrt%289%29%2B4+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > Note that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%289%29+=+-3 ALIGN=MIDDLE  ALT=\"sqrt%289%29+=+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > or +3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2B4+=+1 ALIGN=MIDDLE  ALT=\"-3%2B4+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > The extraneous root of (+3) was introduced when squaring <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282y%2B7%29 ALIGN=MIDDLE  ALT=\"sqrt%282y%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y= 9<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%289%29%2B7%29+%2B+4+=+9 ALIGN=MIDDLE  ALT=\"sqrt%282%289%29%2B7%29+%2B+4+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2825%29+%2B+4+=9 ALIGN=MIDDLE  ALT=\"sqrt%2825%29+%2B+4+=9\"   DISABLED_style= \"max-width:90%; height:auto;\" > Note that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2825%29+=+5 ALIGN=MIDDLE  ALT=\"sqrt%2825%29+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" > or -5<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2B4+=+9 ALIGN=MIDDLE  ALT=\"5%2B4+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" > The extaneous root of (-5) was introduced when squaring <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282y%2B7%29 ALIGN=MIDDLE  ALT=\"sqrt%282y%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "#16<BR>\n" );
document.write( "The geometry of the problem describes a right triangle in which the height is 3 m. and the length of the hypotenuse is 7 m.<BR>\n" );
document.write( "Use the Pythagorean theorem <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > to calculate the third side of this triangle. The hypotenuse is 7 m. so c = 7 and the height is 3 m. so a = 3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%5E2+=+3%5E2+%2B+b%5E2 ALIGN=MIDDLE  ALT=\"7%5E2+=+3%5E2+%2B+b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve for b which is the required length of the insulation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=49+=+9+%2B+b%5E2 ALIGN=MIDDLE  ALT=\"49+=+9+%2B+b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 9 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40+=+b%5E2 ALIGN=MIDDLE  ALT=\"40+=+b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2840%29+=+b ALIGN=MIDDLE  ALT=\"sqrt%2840%29+=+b\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+6.3m ALIGN=MIDDLE  ALT=\"b+=+6.3m\"   DISABLED_style= \"max-width:90%; height:auto;\" > To the nearest tenth.<BR>\n" );
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