document.write( "Question 841617: Jayne has a rectangular swimming pool in her backyard.The pool has a width of 15 feet and a length of 25 feet.The deck that surrounds the pool is 5 feet. \r
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document.write( "What is the area of the deck that surrounds the pool? \n" );
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Algebra.Com's Answer #507067 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! The area of the pool only (ignore the deck) is 15*25 = 375 square feet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you add on the deck, then you have to add on 5 ft to each side so you're really adding on 2*5 = 10 ft to each dimension to 15+10 = 25 by 25+10 = 35 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The dimensions of the pool+deck is 25 by 35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area of this pool+deck combo is 25*35 = 875 square feet\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract the area of the pool only from the pool+deck combo to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "875 - 375 = 500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the area of just the deck is 500 square feet \n" ); document.write( " |