document.write( "Question 841610: Joe's job is to provide technical support to computer users. Suppose the arrival of calls can be modeled by a Poisson distribution with a mean of 9.5 calls per hour. What's the probability that in the next 10 minutes there will be 3 or more calls? Round your answer to the nearest thousandths place.
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #507050 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" );
document.write( "Hi,
\n" );
document.write( "Note:  Using TI Calcuator
\n" );
document.write( "The syntax is 1 – poissoncdf(mean, largest x-value).
\n" );
document.write( "mean/10min  is 9.5/6 = \"%2819%2F2%29%2F6+=+19%2F12\"
\n" );
document.write( "probability that in the next 10 minutes there will be 3 or more calls?
\n" );
document.write( "P(x ≥ 3) = 1 – P(x ≤ 2).
\n" );
document.write( "1 – poissoncdf(19/12, 2). \n" );
document.write( "
\n" );