document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70973>Question 70973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are decreased by 3cm, the area is decreased by 81 cm^2. What were the dimentions of the original square?\r<BR>\n" );
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document.write( "My answer for this one was 15cm by 15cm. Is this correct?\r<BR>\n" );
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document.write( "Thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50704 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yeah you got this right. You can check by finding the area of a square of length 15 cm. 15*15=225 and find the length of a square of 12 cm: 12*12=144 which is 81 away from 225 (ie 225-144=81) </SPAN>\n" );
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