document.write( "Question 841575: How many liters of 6% acid solution must be added to 12 L of a 10% acid solution to make a solution which is 9% acid? \r
\n" ); document.write( "\n" ); document.write( "I know that the( # of liters of acid from the weak soultions ) + ( the # of liters of acid from the strong solution ) = ) the liters of acid I'm the mix solution ) \r
\n" ); document.write( "\n" ); document.write( "I just don't know how to set up the equation. .
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Algebra.Com's Answer #507003 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
let x equal the number of liters of 6% solution and let y equal the number of liters of the 9% solution.\r
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\n" ); document.write( "\n" ); document.write( "the equation should be:\r
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\n" ); document.write( "\n" ); document.write( ".06x + .10*12 = .09*y\r
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\n" ); document.write( "\n" ); document.write( "Since x + 12 will be equal to y, you can replace y with x + 12 to get:\r
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\n" ); document.write( "\n" ); document.write( ".06x + .10*12 = .09*(x+12)\r
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\n" ); document.write( "\n" ); document.write( "now you just solve for x.\r
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\n" ); document.write( "\n" ); document.write( "start with:
\n" ); document.write( ".06x + .10*12 = .09*(x+12)
\n" ); document.write( "simplify to get:
\n" ); document.write( ".06x + 1.2 = .09x + .09*12
\n" ); document.write( "simplify further to get:
\n" ); document.write( ".06x + 1.2 = .09x + 1.08
\n" ); document.write( "subtract .06x from both sides of this equation and subtract 1.08 from both sides of this equation to get:
\n" ); document.write( "1.2 - 1.08 = .09x - .06x
\n" ); document.write( "simplify to get:
\n" ); document.write( ".12 = .03x
\n" ); document.write( "divide both sides of this equation by .03 to get:
\n" ); document.write( ".12/.03 = x which simplifies to x = 4\r
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\n" ); document.write( "\n" ); document.write( "your answer should be x = 4
\n" ); document.write( "this means you mix 4 liters of 6% solution with 12 liters of 10% solution to get 16 liters of 9% solution.
\n" ); document.write( ".06*4 = .24
\n" ); document.write( ".10*12 = 1.2
\n" ); document.write( "add them together to get 1.44 liters of acid.
\n" ); document.write( "divide 1.44 by 16 liters total solution to get .09.
\n" ); document.write( "that's your solution.\r
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