document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70952>Question 70952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist needs 130 milliliters of a 79% solution but has only 29% and 94% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50700 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the required number of ml of 29% solution and 130-x = the required number of ml of 94% solution to make 130 ml of 79% solution.  From this you can write the equation after converting the percentages to their equivalent decimal values:<BR>\n" );
document.write( "0.29x + 0.94(130-x) = 0.79(130) Simplify and solve for x.<BR>\n" );
document.write( "0.29x + 122.2 - 0.94x = 102.7 Combine like-terms.<BR>\n" );
document.write( "-0.65x + 122.2 = 102.7 Subtract 122.2 from both sides.<BR>\n" );
document.write( "-0.65x = -19.5 Divide both sides by -0.65<BR>\n" );
document.write( "x = 30 and 130-x = 130-30 = 100<BR>\n" );
document.write( "The Chemist will require 30 ml of 29% solution and 100 ml of 94% solution.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "0.29(30) + 0.94(100) = 8.7 + 94 = 102.7<BR>\n" );
document.write( "0.79(130) = 102.7<BR>\n" );
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