document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841531>Question 841531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is twice as old as his son..20 years before,the father was four times as old as his son. find their present age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506973 by </B><A HREF=/tutors/aboutme.mpl?userid=Narsinghchauhan8960103366><B>Narsinghchauhan8960103366(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Narsinghchauhan8960103366><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Narsinghchauhan8960103366><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let his son's present age = x years <BR>\n" );
document.write( "So his father's present age = 2x years<BR>\n" );
document.write( "Before 20 years his son's age=(x-20) years<BR>\n" );
document.write( "Before 20 years father's age=(2x-20) years<BR>\n" );
document.write( "4(x-20)=(2x-20)<BR>\n" );
document.write( "4x-80=2x-20<BR>\n" );
document.write( "4x-2x=80-20<BR>\n" );
document.write( "2x=60<BR>\n" );
document.write( "x=30<BR>\n" );
document.write( "His son's present age = 30<BR>\n" );
document.write( "Father's present age=60  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );