document.write( "Question 841330: X times age of John is equal to Y times age of Alice. Difference between their ages is M. John is older to Alice. Find their ages. \r
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Algebra.Com's Answer #506939 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! X times age of John is equal to Y times age of Alice. \n" ); document.write( " Difference between their ages is M. John is older to Alice. \n" ); document.write( " Find their ages. \n" ); document.write( "j = John's age \n" ); document.write( "a = Alice's age \n" ); document.write( ": \n" ); document.write( "\"X times age of John is equal to Y times age of Alice.\" \n" ); document.write( "jx = ay \n" ); document.write( ": \n" ); document.write( "\"Difference between their ages is M. John is older to Alice. \n" ); document.write( "j - a = m \n" ); document.write( "j = a + m \n" ); document.write( "a = j - m \n" ); document.write( "Replace j in the 1st equation with (a+m) \n" ); document.write( "x(a+m) = ay \n" ); document.write( "ax + xm = ay \n" ); document.write( "ax - ay = -xm \n" ); document.write( "Factor out a \n" ); document.write( "a(x-y) = -xm \n" ); document.write( "a = \n" ); document.write( ": \n" ); document.write( "Find John's age \n" ); document.write( "Replace a with (j-m) in the 1st equation \n" ); document.write( "jx = y(j-m) \n" ); document.write( "jx = jy - ym \n" ); document.write( "jx - jy = -ym \n" ); document.write( "Factor out j \n" ); document.write( "j(x-y) = -ym \n" ); document.write( "j = |