document.write( "Question 70955: I have 2 more simultaneous questions that I need help with please. Very confused. Thank you
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document.write( "5x+y=19
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document.write( "2x-y=2\r
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document.write( "and\r
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document.write( "6x+7=20
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document.write( "3x+y=11 \n" );
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Algebra.Com's Answer #50692 by mathman409(67)![]() ![]() ![]() You can put this solution on YOUR website! 5x+y=19 \n" ); document.write( "2x-y=2 \n" ); document.write( "add the equations to cancel 1 variable out, then figure out the other variable. \n" ); document.write( " 5x+y=19 \n" ); document.write( "+ \n" ); document.write( " 2x-y=2 \n" ); document.write( "____________ \n" ); document.write( "7x=21 \n" ); document.write( "x=3\r \n" ); document.write( "\n" ); document.write( "get the other variable using any equation, but this time replace x with the value it has, in this case, 3\r \n" ); document.write( "\n" ); document.write( "15+y=19 \n" ); document.write( "y=19-15 \n" ); document.write( "y=4\r \n" ); document.write( "\n" ); document.write( "CHECK USING THE OTHER EQUATION (this is a very important step if you want to be good at algebra)(assume your answers are right and use the other equation. replace variables with their assumed correct value. if you have the same number on both sides of the equal sign, than you're correct. if you don't...well, than-- you'll just have to start over again)\r \n" ); document.write( "\n" ); document.write( "2(3)-4=2 \n" ); document.write( "6-4=2 \n" ); document.write( "2=2\r \n" ); document.write( "\n" ); document.write( "yay we did it!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |