document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841416>Question 841416</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given tan(theta)=-4/5 and cos(theta)>0, find the exact values of sin(theta) and sec(theta). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506912 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given tan(theta)=-4/5 and cos(theta)>0, find the exact values of sin(theta) and sec(theta).<BR>\n" );
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document.write( "Since tan is negative and cos is positive, theta is in QIV where<BR>\n" );
document.write( "x is positive and y is negative.<BR>\n" );
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document.write( "tan = y/x = -4/5 implies x = 5 and y = -4<BR>\n" );
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document.write( "Then r = sqrt[5^2+4^2] = sqrt(41)<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "sin(t) = y/r = -4/sqrt(41) <BR>\n" );
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document.write( "sec(t) = r/x = sqrt(41)/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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