document.write( "Question 841326: the hypotenuse of right triangle is 1m less than twice the shortest side,if the side is 1m more than the shortest side. find the side of a triangle? \n" ); document.write( "

Algebra.Com's Answer #506777 by hamsanash1981@gmail.com(151) $\"\"$ $\"About$

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Let the shortest side be x ,
\n" ); document.write( "then Hypotenuse = 2x-1 and other side = x+1
\n" ); document.write( "By Pythagoras theorem,\r
\n" ); document.write( "\n" ); document.write( " $\"%282x-1%29%5E2+=+%28x%2B1%29%5E2+%2B+x%5E2\"$
\n" ); document.write( " $\"4x%5E2+-8x+%2B1+=+x%5E2%2B1%2B2x+%2Bx%5E2\"$
\n" ); document.write( " $\"2x%5E2+-6x+=+0\"$
\n" ); document.write( "2x(x-3)=0
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3
\n" ); document.write( "therefore the side of the triange are x,x+1, 2x-1 => 3,4,5 \n" ); document.write( "

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