document.write( "Question 841125: The table shows the revenue of a local automobile dealership. Find the percent of increase in the revenue fro 1998 to 2001. Round to the nearest tenth of a percent. 1998- 105000 2001- 315000 \n" ); document.write( "
Algebra.Com's Answer #506772 by hamsanash1981@gmail.com(151) ![]() You can put this solution on YOUR website! Difference in revenue = 315000 - 105000 = 210000 \n" ); document.write( "Number of intervals between 1998 - 2001 = 3 \n" ); document.write( "% increase = (last term - first term)/first term * no of intervals \n" ); document.write( "% increase = \n" ); document.write( "=200/3 \n" ); document.write( "= 66.67%\r \n" ); document.write( "\n" ); document.write( "The percentage increase is 66.67% \n" ); document.write( " |