document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840626>Question 840626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four times the sum of the first and third of three consecutive odd integers is one less than seven times the middle integer.  Fine the integers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506763 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the consecutive odd number be x,x+2,X+4<BR>\n" );
document.write( "Given that 4(first + third number )= 7 (second) -1<BR>\n" );
document.write( "4(x +x+4 ) = 7(x+2) -1<BR>\n" );
document.write( "8x +16 = 7x +14 -1<BR>\n" );
document.write( "x = 13 - 16<BR>\n" );
document.write( "x = -3<BR>\n" );
document.write( "Then the three numbers are -3, -1,1. </SPAN>\n" );
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