document.write( "Question 841260: The perimeter of a rectangle is 86 inches. The width of the rectangle is 5 less than two times it's length. What is the area of the rectangle? Show all work if possible \r
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Algebra.Com's Answer #506754 by hamsanash1981@gmail.com(151)\"\" \"About 
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Let length be x then, width = x - 5
\n" ); document.write( "perimeter = 86
\n" ); document.write( "2(l+b)=86
\n" ); document.write( "2(x+x-5)=86
\n" ); document.write( "4x-10 =86
\n" ); document.write( "4x = 96
\n" ); document.write( "x = 24
\n" ); document.write( "length = 24
\n" ); document.write( "Width = 24-5=> 19
\n" ); document.write( "area = l*b
\n" ); document.write( "= 24*19
\n" ); document.write( "=456 sq inches\r
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