document.write( "Question 841260: The perimeter of a rectangle is 86 inches. The width of the rectangle is 5 less than two times it's length. What is the area of the rectangle? Show all work if possible \r
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Algebra.Com's Answer #506754 by hamsanash1981@gmail.com(151)![]() ![]() ![]() You can put this solution on YOUR website! Let length be x then, width = x - 5 \n" ); document.write( "perimeter = 86 \n" ); document.write( "2(l+b)=86 \n" ); document.write( "2(x+x-5)=86 \n" ); document.write( "4x-10 =86 \n" ); document.write( "4x = 96 \n" ); document.write( "x = 24 \n" ); document.write( "length = 24 \n" ); document.write( "Width = 24-5=> 19 \n" ); document.write( "area = l*b \n" ); document.write( "= 24*19 \n" ); document.write( "=456 sq inches\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |