document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841268>Question 841268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am very unsure about how to set up the equation for this problem and then how to solve for the amount. The question is;how many liters of a %30 solution must be mixed with 90 liters of a 70% solution to get a 60% solution?? Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506747 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Already given the equation for this.\r<BR>\n" );
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document.write( "Let x = volume of the 30% solution to add,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2830x%2B%2870%29%2890%29%29%2F%28x%2B90%29=60 ALIGN=MIDDLE  ALT=\"%2830x%2B%2870%29%2890%29%29%2F%28x%2B90%29=60\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "This will be a simple linear equation in ONE variable, x.\r<BR>\n" );
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document.write( "The 30, the 70, and the 60, are used as percents.  These could all have been used in their decimal form, and you could redo the equation that way if you are more comfortable with that way. </SPAN>\n" );
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