document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841060>Question 841060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of train A is 12 mph slower than the speed of train B. Train A travels 230 miles in the same time it takes train B to travel 290 miles. Find the speed of each train. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506739 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of train B be x, then speed of A will be x-12.<BR>\n" );
document.write( "Time taken by A = 230/(x-12)<BR>\n" );
document.write( "Time taken By B = 290 / x<BR>\n" );
document.write( "Given that the time taken by train A =  Train B <BR>\n" );
document.write( "Then, 230/(x-12)= 290/x<BR>\n" );
document.write( "=> 23X=29x-348<BR>\n" );
document.write( "=> 6x = 348<BR>\n" );
document.write( "=> x = 58\r<BR>\n" );
document.write( "\n" );
document.write( "therefore the speed of train A is (x-12 = 58-12)46 and Train B is 58. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );