document.write( "Question 841192: 6n-12=n+3\r
\n" ); document.write( "\n" ); document.write( "Okay, so I have no idea on which side to do first...
\n" ); document.write( "When I did the right first I got 15 over 6.
\n" ); document.write( "I don't think that's correct.
\n" ); document.write( "And when I started with the left I ended up with -24
\n" ); document.write( "I checked and both are incorrect.
\n" ); document.write( "Help? Thanks ! \n" ); document.write( "

Algebra.Com's Answer #506700 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
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Solved by pluggable solver: Linear Equation Solver

$\"6n-12=n%2B3\"$ Start with the given equation.

$\"6n=n%2B3%2B12\"$ Add $\"12\"$ to both sides.

$\"6n-n=3%2B12\"$ Subtract $\"n\"$ from both sides.

$\"5n=3%2B12\"$ Combine like terms on the left side.

$\"5n=15\"$ Combine like terms on the right side.

$\"n=%2815%29%2F%285%29\"$ Divide both sides by $\"5\"$ to isolate $\"n\"$ .

$\"n=3\"$ Reduce.

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So the solution is $\"n=3\"$

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