document.write( "Question 841172: find the lengths of each side of the right triangle
\n" ); document.write( "short leg is 2x+1
\n" ); document.write( "long leg is 11x+5
\n" ); document.write( "hypotenuse is 12x+1
\n" ); document.write( "I know that first you're suppose to write the problem out like this
\n" ); document.write( "(12x+1)^2=(2x+1)^2+(11x+5)^2
\n" ); document.write( "but after this I got lost
\n" ); document.write( "please help and break it down as much as possible
\n" ); document.write( "please and thank you :D
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Algebra.Com's Answer #506680 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
So far so good. Now we just need to solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"%2812x%2B1%29%5E2=%282x%2B1%29%5E2%2B%2811x%2B5%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2812x%2B1%29%2812x%2B1%29=%282x%2B1%29%282x%2B1%29%2B%2811x%2B5%29%2811x%2B5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"144x%5E2%2B12x%2B12x%2B1=4x%5E2%2B2x%2B2x%2B1%2B121x%5E2%2B55x%2B55x%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "\"144x%5E2%2B24x%2B1=125x%5E2%2B114x%2B26\"\r
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\n" ); document.write( "\n" ); document.write( "\"144x%5E2%2B24x%2B1-125x%5E2-114x-26=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"19x%5E2-90x-25=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now from here, you could factor, but I like using the quadratic formula (since it always works for any quadratic)\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"19%2Ax%5E2-90%2Ax-25=0\" ( notice \"a=19\", \"b=-90\", and \"c=-25\")
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\n" ); document.write( " \"x+=+%28--90+%2B-+sqrt%28+%28-90%29%5E2-4%2A19%2A-25+%29%29%2F%282%2A19%29\" Plug in a=19, b=-90, and c=-25
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\n" ); document.write( " \"x+=+%2890+%2B-+sqrt%28+%28-90%29%5E2-4%2A19%2A-25+%29%29%2F%282%2A19%29\" Negate -90 to get 90
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\n" ); document.write( " \"x+=+%2890+%2B-+sqrt%28+8100-4%2A19%2A-25+%29%29%2F%282%2A19%29\" Square -90 to get 8100 (note: remember when you square -90, you must square the negative as well. This is because \"%28-90%29%5E2=-90%2A-90=8100\".)
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\n" ); document.write( " \"x+=+%2890+%2B-+sqrt%28+8100%2B1900+%29%29%2F%282%2A19%29\" Multiply \"-4%2A-25%2A19\" to get \"1900\"
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\n" ); document.write( " \"x+=+%2890+%2B-+sqrt%28+10000+%29%29%2F%282%2A19%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%2890+%2B-+100%29%2F%282%2A19%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%2890+%2B-+100%29%2F38\" Multiply 2 and 19 to get 38
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%2890+%2B+100%29%2F38\" or \"x+=+%2890+-+100%29%2F38\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%2890+%2B+100%29%2F38\"
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\n" ); document.write( " \"x=190%2F38\" Add the terms in the numerator
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\n" ); document.write( " \"x=5\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"x=5\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%2890+-+100%29%2F38\"
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\n" ); document.write( " \"x=-10%2F38\" Subtract the terms in the numerator
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\n" ); document.write( " \"x=-5%2F19\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"x=-5%2F19\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"x=5\" or \"x=-5%2F19\"
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\n" ); document.write( "\n" ); document.write( "Now because the hypotenuse is \"12x%2B1\", this means that when \"x+=+-5%2F19\" the hypotenuse will be \"12x%2B1+=+12%28-5%2F19%29%2B1=-2.1578947368421\". But we can't have a negative length. So \"x+=+-5%2F19\" cannot be allowed as a solution.\r
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\n" ); document.write( "\n" ); document.write( "That means \"x+=+5\" is the only solution.\r
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\n" ); document.write( "\n" ); document.write( "Now plug in \"x+=+5\" into each expression\r
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\n" ); document.write( "\n" ); document.write( "Short Leg: \"2x+%2B+1+=+2%2A5%2B1+=+11\"\r
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\n" ); document.write( "\n" ); document.write( "Long Leg: \"11x+%2B+5+=+11%2A5%2B5+=+60\"\r
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\n" ); document.write( "\n" ); document.write( "Hypotenuse: \"12x+%2B+1+=+12%2A5%2B1+=+61\"\r
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\n" ); document.write( "\n" ); document.write( "Summary:\r
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\n" ); document.write( "\n" ); document.write( "Short Leg: 11 units\r
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\n" ); document.write( "\n" ); document.write( "Long Leg: 60 units\r
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\n" ); document.write( "\n" ); document.write( "Hypotenuse: 61 units
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