document.write( "Question 841124: a person bought 4 adult tickets and 2 children tickets and spent $80.00. How much did the tickets cost for adult and children? Please show your work while working towards your solution.\r
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document.write( "My equation is 4a + 2c = $80.00... then I solve for each one.
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document.write( "4a + 2c = $80.00 so…. Need to get s by itself so subtract 2c
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document.write( "4a = $80.00 – 2c… then divide by 4
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document.write( "a = $80.00/4 – 2c/4… then simplify
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document.write( "a = $20.00 – 1/2c
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document.write( "2c = $80.00 – 4a
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document.write( "C = $80.00/2 – 4a/2
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document.write( "C = $40.00 -2a\r
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document.write( "I don't know where to go from here. I believe my answers are 15 and 10 but how do I show that
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Algebra.Com's Answer #506667 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! There is not enough info to get one answer. \n" ); document.write( "4a + 2c = 80 \n" ); document.write( "If c=$0 then a=$20 \n" ); document.write( "If a=$0 then c=$40 \n" ); document.write( "$15=a and $10 =c is a nice choice but it isn't the only one. \n" ); document.write( "A = n and C = 40-2n \n" ); document.write( "a=1 c=38 \n" ); document.write( "a=2 c=36 \n" ); document.write( "a=3 c=34 \n" ); document.write( "a=13 c=14 \n" ); document.write( "a=14 c=12 \n" ); document.write( "a=15 c=10 your choice \n" ); document.write( "a=16 c=8 \n" ); document.write( "a=17 c=6 \n" ); document.write( "a=18 c=4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |