document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840753>Question 840753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the values of the trigonometric functions of t from the given information tan(t)=1/4 terminal point of t is in quadrant III </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506662 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the values of the trigonometric functions of t from the given information tan(t)=1/4 terminal point of t is in quadrant III<BR>\n" );
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document.write( "Note: In QIII, x is negative and y is negative.<BR>\n" );
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document.write( "Definition:: tan = y/x<BR>\n" );
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document.write( "Since tan(t) = 1/4, y = -1 and x = -4<BR>\n" );
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document.write( "Then r = sqrt[4^2 + 1^2] = sqrt(17)<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "sin = y/r = -1/sqrt(17)<BR>\n" );
document.write( "cos = x/r = -4/sqrt(17)<BR>\n" );
document.write( "tan = 1/4<BR>\n" );
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document.write( "csc, sec, and cot are the inverse of sin, cos, and tan<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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