document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=841065>Question 841065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Without using a calculator, choose the point on the terminal side of &#952;. &#952; = 5&#960;/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506651 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Without using a calculator, choose the point on the terminal side of &#952;. &#952; = 5&#960;/4<BR>\n" );
document.write( "5&#960;/4=&#960;+&#960;/4(rotate counter-clockwise &#960; plus &#960;/4 which places a reference angle of &#960;/4 in quadrant III in which sin<0, cos<0.<BR>\n" );
document.write( "Point on terminal side of unit circle:(-&#8730;2/2,-&#8730;2/2) </SPAN>\n" );
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