document.write( "Question 70905: A coin bank contains nickels, dimes, and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coins are in the bank? \n" ); document.write( "
Algebra.Com's Answer #50653 by mathmaven53(29)![]() ![]() ![]() You can put this solution on YOUR website! Let number of nickels be N \n" ); document.write( "number of dimes be D \n" ); document.write( "number of quarters be Q \n" ); document.write( "By the conditions of the problem \n" ); document.write( "D= 2Q \n" ); document.write( "Q = N + 11\r \n" ); document.write( "\n" ); document.write( "The value of the coins is .05N + .1D + .25Q = 5.45\r \n" ); document.write( "\n" ); document.write( "We have N = Q - 11\r \n" ); document.write( "\n" ); document.write( "Substitute into equation for value of coins\r \n" ); document.write( "\n" ); document.write( " .05(Q - 11) + .2Q + .25Q = 5.45\r \n" ); document.write( "\n" ); document.write( " Solving for Q gives Q = 12\r \n" ); document.write( "\n" ); document.write( " Then N = Q - 11 \n" ); document.write( " = 1\r \n" ); document.write( "\n" ); document.write( " D = 2Q\r \n" ); document.write( "\n" ); document.write( " = 24\r \n" ); document.write( "\n" ); document.write( " 1 nickel, 24 dimes , 12 quarters \n" ); document.write( " |