document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70907>Question 70907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the two-digit number whose tens digit is 3 less than the units digit. The original number is 6 more than 4 times the sum of the digits. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50650 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmaven53><B>mathmaven53(29)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmaven53><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be units digit then by condition of problem tens digit is x-3<BR>\n" );
document.write( "The origonal number is 10(x-3) + x\r<BR>\n" );
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document.write( " The sum of the digits is x-3 + x\r<BR>\n" );
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document.write( " The origonal number is six more than four times the sum of the digits \r<BR>\n" );
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document.write( " 10(x-3)+x = 4(x-3 + x) + 6\r<BR>\n" );
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document.write( " Simplify the left and right sides\r<BR>\n" );
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document.write( "  11x - 30 = 8x - 6\r<BR>\n" );
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document.write( "   From this \r<BR>\n" );
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document.write( "   3x  = 24\r<BR>\n" );
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document.write( "    x = 8<BR>\n" );
document.write( "   <BR>\n" );
document.write( " The number is 58 </SPAN>\n" );
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