document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840831>Question 840831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Translate into an equation. (Use x to represent the smaller number.)<BR>\n" );
document.write( "The sum of two numbers is fifteen. Three times the smaller is equal to two times the larger. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506486 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be smaller number and y be larger number then, <BR>\n" );
document.write( "3x = 2y<BR>\n" );
document.write( "x =2y/3<BR>\n" );
document.write( "x+ y = 15<BR>\n" );
document.write( "2y/3 + y = 15<BR>\n" );
document.write( "5y/3 = 15<BR>\n" );
document.write( "y =9\r<BR>\n" );
document.write( "\n" );
document.write( "x = 2*9/3<BR>\n" );
document.write( "x = 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );