document.write( "Question 840729: Find the value of sin theta if tan theta= negative square root of 55 divided by 5. When cosine theta <0. \n" ); document.write( "

Algebra.Com's Answer #506483 by hamsanash1981@gmail.com(151) $\"\"$ $\"About$

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Given that tan theta = - (55)^(1/2)/5
\n" ); document.write( "the opposite side = (55)^(1/2)
\n" ); document.write( "adjacent side = -5 (since the condition given is cosine theta is < 0)
\n" ); document.write( "hypotenuse = square root of ( ((55)^(1/2))^2 + (-5)^2)
\n" ); document.write( "= Square root of (55 + 25)
\n" ); document.write( "=square root of (80)
\n" ); document.write( "= 4 *(5)^(1/2)\r
\n" ); document.write( "\n" ); document.write( "Sine theta = square root of (55)/ 4*square root of (5)
\n" ); document.write( "= square root(5)*square root(11)/4* Square root(5)
\n" ); document.write( "=square root(11)/4\r
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