document.write( "Question 70902: 2(p-3)+6=4p-10 \n" ); document.write( "
Algebra.Com's Answer #50648 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "Multiply out 2 times (p - 3) by multiplying 2 times each of the terms in the parentheses. \n" ); document.write( "When you do this multiplication the result is 2p -6. Substitute this into the equation \n" ); document.write( "in place of 2(p-3) to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Note on the left side that the -6 and the +6 cancel each other out so that the left side \n" ); document.write( "reduces to just 2p. The equation is now: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The goal is to get all the terms that contain p on the left side. So what we need to \n" ); document.write( "do is subtract 4p from the left side. But if we do that, we have to subtract 4p from the \n" ); document.write( "left side also. [Whatever we do to one side of the equation, we have to do it to the \n" ); document.write( "other side too.] By subtracting 4p from both sides we reduce the equation to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now we have to get rid of the -2 that multiplies p. We do this by dividing both sides of \n" ); document.write( "the equation by -2. On the left side the -2 divides into the -2 multiplier of p to become \n" ); document.write( "just 1. And 1p is written as just p. On the right side when the -10 is divided by -2, \n" ); document.write( "the result is +5. Therefore, the answer is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can check this answer out by returning to the original equation and replacing p \n" ); document.write( "by 5. Then work out both sides of the equation and see if the left side equals the right \n" ); document.write( "side. If it does then the solution of p=5 works to keep the equation in balance. \n" ); document.write( "So first replace p by 5 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The 5-3 in parentheses equals 2 and when it is multiplied by the 2 in front of the parens \n" ); document.write( "the result is 4. So the left side equals 4 + 6. The 5*4 in the parentheses on the right \n" ); document.write( "side becomes 20. So the right side equals 20 -10. In equation form this is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Obviously the left side is 10 and so is the right side. Therefore p = 5 is a solution to \n" ); document.write( "the original equation. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem and how you use algebraic steps to work the \n" ); document.write( "problem out to a solution. \n" ); document.write( " \n" ); document.write( " |