document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840859>Question 840859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm am trying to do a proof where (sinx - 2 + 1/sinx)/(sinx - 1/sinx) = (sinx - 1)/(sinx + 1)<BR>\n" );
document.write( "I have attempted to convert 1/sinx to cscx then cross multiply which ends up equalizing the top and bottom of the left hand side of the equation to 1 and I've also tried changing sinx -2 + 1/sinx to sin^2x/sinx + 1/sinx -2 over sin^2x/sinx - 1/sinx but then I just get stuck with the 2 in the way of everything. I'm just needing help on how to solve the problem and not just have the answer given to me </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506479 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LHS (sinx-2 +1/sinx)/(sinx - 1/sinx)<BR>\n" );
document.write( "Evaluating numerator (sin^2x - 2sinx +1)/sinx  => (Sin^2x -sinx -sinx +1)/sinx<BR>\n" );
document.write( "Evaluating denominator (sin^2x - 1)/sinx<BR>\n" );
document.write( "now combining numerator and deominator<BR>\n" );
document.write( "=((sin^2x - sinx - sinx +1)/sinx )/((sin^2x -1)/sinx)<BR>\n" );
document.write( "= ((sinx(sinx-1)-(sinx-1))/ (sin^2x-1)<BR>\n" );
document.write( "=  (sinx-1)(sinx-1)/(sinx-1)(sinx + 1)<BR>\n" );
document.write( "=(sinx -1)/(sinx + 1)<BR>\n" );
document.write( "= RHS </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );