document.write( "Question 840833: A rectangle has a length that is 6 feet more than the width. Its perimeter is 100 feet. What is the area? \n" ); document.write( "

Algebra.Com's Answer #506477 by hamsanash1981@gmail.com(151) $\"\"$ $\"About$

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Let the breath of the rectangle be x feet and lenght is x+ 6 feet.
\n" ); document.write( "perimeter = 100
\n" ); document.write( "2(l+B) =100
\n" ); document.write( "2(x+6 + x)=100
\n" ); document.write( "4x +12 = 100
\n" ); document.write( "4x = 100-12
\n" ); document.write( "4x = 88
\n" ); document.write( "x = 22
\n" ); document.write( "length = 22 +6
\n" ); document.write( "=28
\n" ); document.write( "Area of rectangle = l* b
\n" ); document.write( "= 22*28
\n" ); document.write( "=616 sq feet \n" ); document.write( "

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