document.write( "Question 840869: in 4 years John will be four thirds Graces age 5 years ago John was one year more than twice Grace's age how old are John Grace now? \n" ); document.write( "
Algebra.Com's Answer #506458 by hamsanash1981@gmail.com(151)\"\" \"About 
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let Grace's present age be x, then after four years Grace age will be x+ 4
\n" ); document.write( "John's age will be = 4/3(x+4) and present age of John = 4/3(x+4)-4
\n" ); document.write( "five years ago Grace age will be x-5
\n" ); document.write( "John's age = present age -5 => 4/3(x+4)-4-5 => 4/3(x+4)-9 --- 1
\n" ); document.write( "Given that John's 5 years ago was one year more than twice the Grace's age
\n" ); document.write( "the John's age = 2(x-5)+1 ---2\r
\n" ); document.write( "\n" ); document.write( "Equating equation 1 and 2 we have
\n" ); document.write( " 4/3(x+4)-9 = 2(x-5)+1
\n" ); document.write( "4/3(x+4) = 2x - 10 + 1 + 9
\n" ); document.write( "(4x + 16)/3 = 2x
\n" ); document.write( "4x + 16 =6x
\n" ); document.write( "16 = 2x
\n" ); document.write( "x = 8\r
\n" ); document.write( "\n" ); document.write( "Then john's persent age = 4/3(x+4)-4
\n" ); document.write( "4/3(12)-4
\n" ); document.write( "=12
\n" ); document.write( "therefore John and Grace are 12 and 8 years old
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