document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840879>Question 840879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Decker invested a certain amount of money in bonds yielding 3% a year and twice as much in bonds yielding 5% a year. If his total annual income from the two investments was $208, how much did he invest in<BR>\n" );
document.write( "each type of bond?\r<BR>\n" );
document.write( "\n" );
document.write( "Please explain to me how to sole this!!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506448 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the amount invested in bonds yielding 3% be x <BR>\n" );
document.write( "then twice as much invested in bonds yielding 5% will be 2x.<BR>\n" );
document.write( "the number of years is 1.<BR>\n" );
document.write( "simple interest for 3% bond = (x*1*3)/100 => 3x/100<BR>\n" );
document.write( "simple interest for 5% bond = (2x*1*5)/100 => 10X/100<BR>\n" );
document.write( "Given that the total income of the investments was 208, then<BR>\n" );
document.write( "3X/100 + 10X/100 = 208\r<BR>\n" );
document.write( "\n" );
document.write( "3x+10x = 20800<BR>\n" );
document.write( "13x = 20800<BR>\n" );
document.write( "x=1600<BR>\n" );
document.write( "therefore the money invested at 3% interest is $1,600 and money invested in 5% is 2*1600 = $3,200.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );