document.write( "Question 840759: Mr. Morton invested $1400, part at 5% and the rest at 8%. His total annual income from these investments was $100. Find the amount he
\n" ); document.write( "invested at each rate.
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\n" ); document.write( "\n" ); document.write( "Please help me solve this. I know this much:\r
\n" ); document.write( "\n" ); document.write( "X=amount at 5%
\n" ); document.write( "Y=amount at 8%
\n" ); document.write( "X+Y=100
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Algebra.Com's Answer #506445 by hamsanash1981@gmail.com(151)\"\" \"About 
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\n" ); document.write( "x = amount at 5%
\n" ); document.write( "y = amount at 8%\r
\n" ); document.write( "\n" ); document.write( "then X + Y = 1400 ---1
\n" ); document.write( "Let the number of years be 1.
\n" ); document.write( "simple interest of X = (X*1*5)/100 => 5x/100
\n" ); document.write( "Simple interest of Y = (Y*1*8)/100 => 8y/100
\n" ); document.write( "Given that his total annual returns from these investment was 100 then,\r
\n" ); document.write( "\n" ); document.write( "5x/100 + 8y/100 = 100 ---2\r
\n" ); document.write( "\n" ); document.write( "Multiplying equation 2 by 100\r
\n" ); document.write( "\n" ); document.write( "5x + 8y = 10000 ---3\r
\n" ); document.write( "\n" ); document.write( "Solving equ 1 and 3\r
\n" ); document.write( "\n" ); document.write( " 8x + 8y = 11200
\n" ); document.write( " 5x + 8y = 10000
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\n" ); document.write( " 3x = 1200
\n" ); document.write( " x = 400
\n" ); document.write( "then Y = 1400 - 400
\n" ); document.write( "Y = 1000\r
\n" ); document.write( "\n" ); document.write( "therefore 400 invested at 5% and 1000 invested at 8%.
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