document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840771>Question 840771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes 2 hours for a small plane to travel 390 miles with the wind. Going against the wind, the plane can travel 330 miles in the same amount of time. Find the speed of the plane in still air and the speed of the wind. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506443 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> speed = distance / time taken\r<BR>\n" );
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document.write( "speed along with the wind a = 390/ 2 => 195 miles/hour\r<BR>\n" );
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document.write( "speep against the wind b = 330/2 => 165 miles/ hour\r<BR>\n" );
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document.write( "Speed of still air = (speed along the wind + speed against the wind)/2\r<BR>\n" );
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document.write( "speed of the wind = (speed along the wind - speed against the wind)/2\r<BR>\n" );
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document.write( "speed of still air = (195+165)/2 => 360/2 => 180\r<BR>\n" );
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document.write( "speed of the wind = (195-165)/2 => 30/2 => 15 </SPAN>\n" );
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