document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=840815>Question 840815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve the following question . . . . Thanks!\r<BR>\n" );
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document.write( "Find 4 consecutive integers such that 3 times the sum of the first and third is 84 greater than the opposite of the second.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #506430 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=506430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find 4 consecutive integers<BR>\n" );
document.write( "n, (n+1), (n+2), (n+3)<BR>\n" );
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document.write( " such that 3 times the sum of the first and third is 84 greater than the opposite of the second<BR>\n" );
document.write( "3[n + n+2)] = -(n+1) + 84<BR>\n" );
document.write( "3(2n+2) = -n - 1 + 84<BR>\n" );
document.write( "6n + 6 = -n + 83<BR>\n" );
document.write( "6n + n = 83 - 6<BR>\n" );
document.write( "7n = 77<BR>\n" );
document.write( "n = 77/7<BR>\n" );
document.write( "n = 11, 12, 13, 14 are the four integers:<BR>\n" );
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document.write( "See if that works<BR>\n" );
document.write( " 3(11+13) = -12 + 84<BR>\n" );
document.write( " 3(24) = 72<BR>\n" );
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