document.write( "Question 840724: Okay this is the problem and i need to use elimination or substitution to solve. I have no idea how to get the equations.\r
\n" ); document.write( "\n" ); document.write( "A motorboat can go 12 miles downstream on a river in 20 minutes. It takes 30 minutes for this boat to go back upstream the same 12 miles. Find the speed of the current.
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Algebra.Com's Answer #506426 by ankor@dixie-net.com(22740)\"\" \"About 
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A motorboat can go 12 miles downstream on a river in 20 minutes.
\n" ); document.write( " It takes 30 minutes for this boat to go back upstream the same 12 miles.
\n" ); document.write( " Find the speed of the current.
\n" ); document.write( ":
\n" ); document.write( "The idea is to understand what's going on here
\n" ); document.write( "We probably want the speeds in mph, therefore
\n" ); document.write( "change 20 min to 1/3 of an hr
\n" ); document.write( "change 30 min to 1/2 hr
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\n" ); document.write( "let s = the speed of the boat in still water
\n" ); document.write( "let c = rate of the current
\n" ); document.write( "then
\n" ); document.write( "(s+c) = effective speed down stream
\n" ); document.write( "and
\n" ); document.write( "(s-c) = effective speed upstream
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation for each way; dist = speed * time
\n" ); document.write( "\"1%2F3\"(s+c) = 12; downstream
\n" ); document.write( "\"1%2F2\"(s-c) = 12; upstream
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\n" ); document.write( "Simplify this, multiply the 1st equation by 3, the 2nd equation by 2
\n" ); document.write( "s + c = 36
\n" ); document.write( "s - c = 24
\n" ); document.write( "---------------Adding eliminates c, find s
\n" ); document.write( "2s = 60
\n" ); document.write( "s = 60/2
\n" ); document.write( "s = 30 mph in still water
\n" ); document.write( ":
\n" ); document.write( "But they want the speed of the current
\n" ); document.write( "s + c = 36
\n" ); document.write( "replace s with 30
\n" ); document.write( "30 + c = 36
\n" ); document.write( "c = 36 - 30
\n" ); document.write( "c = 6 mph is the current
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\n" ); document.write( "Check this in the 1st original equation
\n" ); document.write( "\"1%2F3\"(30+6) =
\n" ); document.write( "\"1%2F3\"* 36 = 12
\n" ); document.write( ":
\n" ); document.write( "You can confirm this in the 2nd original equation
\n" ); document.write( "\"1%2F2\"(s-c) =
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\n" ); document.write( "Is this starting to make sense to you now?
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