document.write( "Question 840724: Okay this is the problem and i need to use elimination or substitution to solve. I have no idea how to get the equations.\r
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document.write( "A motorboat can go 12 miles downstream on a river in 20 minutes. It takes 30 minutes for this boat to go back upstream the same 12 miles. Find the speed of the current.
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document.write( "(btw it won't let me choose a topic) \n" );
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Algebra.Com's Answer #506426 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A motorboat can go 12 miles downstream on a river in 20 minutes. \n" ); document.write( " It takes 30 minutes for this boat to go back upstream the same 12 miles. \n" ); document.write( " Find the speed of the current. \n" ); document.write( ": \n" ); document.write( "The idea is to understand what's going on here \n" ); document.write( "We probably want the speeds in mph, therefore \n" ); document.write( "change 20 min to 1/3 of an hr \n" ); document.write( "change 30 min to 1/2 hr \n" ); document.write( ": \n" ); document.write( "let s = the speed of the boat in still water \n" ); document.write( "let c = rate of the current \n" ); document.write( "then \n" ); document.write( "(s+c) = effective speed down stream \n" ); document.write( "and \n" ); document.write( "(s-c) = effective speed upstream \n" ); document.write( ": \n" ); document.write( "Write a distance equation for each way; dist = speed * time \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Simplify this, multiply the 1st equation by 3, the 2nd equation by 2 \n" ); document.write( "s + c = 36 \n" ); document.write( "s - c = 24 \n" ); document.write( "---------------Adding eliminates c, find s \n" ); document.write( "2s = 60 \n" ); document.write( "s = 60/2 \n" ); document.write( "s = 30 mph in still water \n" ); document.write( ": \n" ); document.write( "But they want the speed of the current \n" ); document.write( "s + c = 36 \n" ); document.write( "replace s with 30 \n" ); document.write( "30 + c = 36 \n" ); document.write( "c = 36 - 30 \n" ); document.write( "c = 6 mph is the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the 1st original equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You can confirm this in the 2nd original equation \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Is this starting to make sense to you now? \n" ); document.write( " \n" ); document.write( " |