document.write( "Question 840429: A computer shop builds PC'S from shipments of parts it receives from various suppliers. The number of defective hard drives per shipment is to be modeled as a random variable X. The random variable is assumed to have the following distribution:\r
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document.write( "X _________ P(x)
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document.write( "0 _________ 0.55
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document.write( "1 _________ 0.15
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document.write( "2 _________ 0.10
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document.write( "3 _________ 0.10
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document.write( "4 _________ 0.05
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document.write( "5 _________ 0.05\r
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document.write( "What is the probability that a shipment will have more than two defective hard drives?\r
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document.write( "Can you provide me an example that answers this similar question in steps that will help me practice? \r
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document.write( "Thank you,
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document.write( "Becky \n" );
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Algebra.Com's Answer #506395 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A computer shop builds PC'S from shipments of parts it receives from various suppliers. The number of defective hard drives per shipment is to be modeled as a random variable X. The random variable is assumed to have the following distribution: \n" ); document.write( "X _________ P(x) \n" ); document.write( "0 _________ 0.55 \n" ); document.write( "1 _________ 0.15 \n" ); document.write( "2 _________ 0.10 \n" ); document.write( "3 _________ 0.10 \n" ); document.write( "4 _________ 0.05 \n" ); document.write( "5 _________ 0.05 \n" ); document.write( "========================= \n" ); document.write( "What is the probability that a shipment will have \n" ); document.write( "more than two defective hard drives?\r \n" ); document.write( "\n" ); document.write( "P(more than 2) = P(x=3)+P(x=4)+P(x=5) = 0.10+0.05+0.05 = 0.20 \n" ); document.write( "--------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------------- \n" ); document.write( " |