document.write( "Question 840600: Find the dimensions of a rectangle whose area s 575square cm and whose perimeter is 96cm \n" ); document.write( "
Algebra.Com's Answer #506331 by LinnW(1048)\"\" \"About 
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set l = length
\n" ); document.write( "w = width
\n" ); document.write( "l*w = area
\n" ); document.write( "l*w = 575
\n" ); document.write( "2l + 2w = 96
\n" ); document.write( "solve for l
\n" ); document.write( "add -2w to each side
\n" ); document.write( "2l = 96 -2w
\n" ); document.write( "divide by 2
\n" ); document.write( "l = 48 -w
\n" ); document.write( "substitute 48 -w for l in l*w = 575
\n" ); document.write( "(48-w)(w) = 575
\n" ); document.write( "48w - w^2 = 575
\n" ); document.write( "add -575 to each side
\n" ); document.write( "-w^2 +48w -575 = 0
\n" ); document.write( "multiply by -1
\n" ); document.write( "w^2 -48w + 575 = 0
\n" ); document.write( "(w - 23)(w - 25) = 0
\n" ); document.write( "w = 23 or w = 25
\n" ); document.write( "Our two dimensions are 23 and 25
\n" ); document.write( "23*25 gives area
\n" ); document.write( "2(23) + 2(25) = 96\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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